PHP & MySQL – Like Clause Example
PHP uses mysqli query() or mysql_query() function to select records in a MySQL table using Like clause. This function takes two parameters and returns TRUE on success or FALSE on failure.
Syntax
$mysqli->query($sql,$resultmode)
Sr.No. | Parameter & Description |
---|---|
1 |
$sql Required – SQL query to select records in a MySQL table using Like Clause. |
2 |
$resultmode Optional – Either the constant MYSQLI_USE_RESULT or MYSQLI_STORE_RESULT depending on the desired behavior. By default, MYSQLI_STORE_RESULT is used. |
Example
Try the following example to select a record using like clause in a table −
Copy and paste the following example as mysql_example.php −
<html> <head> <title>Using Like Clause</title> </head> <body> <?php $dbhost = ''localhost $dbuser = ''root $dbpass = ''root@123 $dbname = ''TUTORIALS $mysqli = new mysqli($dbhost, $dbuser, $dbpass, $dbname); if($mysqli->connect_errno ) { printf("Connect failed: %s<br />", $mysqli->connect_error); exit(); } printf(''Connected successfully.<br />''); $sql = ''SELECT tutorial_id, tutorial_title, tutorial_author, submission_date FROM tutorials_tbl where tutorial_author like "Mah%" $result = $mysqli->query($sql); if ($result->num_rows > 0) { while($row = $result->fetch_assoc()) { printf("Id: %s, Title: %s, Author: %s, Date: %d <br />", $row["tutorial_id"], $row["tutorial_title"], $row["tutorial_author"], $row["submission_date"]); } } else { printf(''No record found.<br />''); } mysqli_free_result($result); $mysqli->close(); ?> </body> </html>
Output
Access the mysql_example.php deployed on apache web server and verify the output. Here we”ve entered multiple records in the table before running the select script.
Connected successfully. Id: 1, Title: MySQL Tutorial, Author: Mahesh, Date: 2021 Id: 2, Title: HTML Tutorial, Author: Mahesh, Date: 2021 Id: 3, Title: PHP Tutorial, Author: Mahesh, Date: 2021